The mass of 2 mol of MgCl2 is: g
Mass of 1 mole of MgCl2=(24+35.5×2) = 95 g Therefore, mass of 2 moles of MgCl2=95×2g=190 g
Calculate the normal freezing point of a sample of sea water containing 3.8 % nacl and 0.12 % of mgcl2 by mass given kf = 1.86 K kg/ mol molar mass of nacl 58.5 and mgcl2 95 g/mol