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Question

The mass of a non-volatile solute of molar mass 40 g mol1, which on dissolution in 57 g octane to reduces the vapour pressure of octane by 20%, is

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Solution

Relative lowering of vapour pressure(RLVP) is a colligative property given by
P0PsP0=Xb=nBnA+nB
Here A represents solute, B represent solvent (octane) and all other terms have their ususal meanings.
RLVP=nBnA=P0PsP0=0.2
=wB/4057/114+wB/40=0.2
wB=5


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