Question

The mass of a specimen of a ferromagnetic material is $0.6kg$ and its density is $7.8\times {10}^{3}kg/m^3$. If the area of hysteresis loop of alternating magnetising field of frequency $50Hz$ is $0.722MKS$ units then the hysteresis loss per second will be-

• A. $277.7\times {10}^{-5}$ Joule
• B. $277.7\times {10}^{-6}$ Joule
• C. $277.7\times {10}^{-4}$ Joule
• D. $277.7\times {10}^{-7}$ Joule

Answer 1

The correct option is A $277.7\times {10}^{-5}$ Joule

Given: m=0.6 kg, density= 7.8$\times {10}^3$ frequency=50Hz, A=0.722

Solution: As we know the formula of hysteresis loss per second :

W=$Volume\times \nu \times A=\frac{0.6}{7.8\times {10}^3}\times 50\times 0.722$

W=277.7 $\times {10}^{-5}$

Hence the correct option is A.