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Question

The mass of an electron is 9.1 × 1031 kg. If its K.E. is 3.0 × 1025 J, calculate its wavelength.

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Solution

From de Broglie’s equation,
λ=hmv
Given, Kinetic energy (K.E) of the electron = 3.0 × 1025 J
Since K.E=12mv2Velocity(v)=2K.Em =2(3.0×1025J)9.10939×1031kg =6.5866×104 v=811.579ms1
Substituting the value in the expression of λ:
λ=6.626×1034Js(9.10939×1031kg)(811.579ms1)λ=8.9625×107m
Hence, the wavelength of the electron is 8.9625 × 107 m.


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