Question

The maximum amplitude for an amplitude modulated wave is found to be $12\text{V}$ while the minimum aplitude is found to be$3\text{V}$. The modulation index is $0.6x$ where $x$ is

Answer 1

The modulation index is given by
$\mu =\frac{V_{max}-V_{min}}{V_{max}+V_{min}}$, where $V_{max}$ and $V_{min}$ are maximum amplitude and minimum amplitude for an amplitude modulated wave respectively.
$\therefore \mu =\frac{(12-3)}{(12+3)}=\frac{9}{15}=0.6$
Thus, value of $x$ is $1$.