CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The maximum height attained by a projectile is increased by 10%. Keeping the angle of projection constant, what is the percentage increase in the time of flight?

A
5%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
20%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
40%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 5%
Let the initial velocity of projection be u, the initial angle of projection θ and time of flight be t.

Initial max. height is, h=(u2sin2θ)2g

Time of flight,t=2usinθg

t2=4u2sin2θg2

t2=(8g)[(u2sin2θ)2g]=(8g)h

Therefore,

T2t2=Hh

Now, new height, H=h+(10100)h=(1110)h

Hh=1110

And,

T2t2=1110

Tt=1.05

Tt1=0.05

(Tt)t=0.05

(Tt)t×100=5%

Thus, the % increase in time of flight is 5%.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basketball
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon