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Question

The maximum number of isomers (including stereoisomers) that are possible on monochlorination of the following compound is


A
8
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B
6
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C
4
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D
2
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Solution

The correct option is A 8
CH3CH2CH3|C|HCH2CH2Cl Enantiomeric pair = 2
CH3CH2CH3|C|HC|ClHCH3 Two enantiomeric pair = 4
CH3CH2CH3|C|ClCH2CH3=1
CH3CH2CH2Cl|C|HCH2CH3=1
Total = 2 + 4 + 1 + 1 = 8

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