Question

The maximum range of a bullet fired from a toy pistol mounted on a car at rest Ro = 40m. What will the acute angle of inclination of the pistol for maximum range when the car is a direction of firing with uniform velocity v = 20 m/s, on a horizontal surface? (g = 10 n)

• A. ${30}^{\circ }$
• B. ${67.5}^{\circ }$
• C. ${75}^{\circ }$
• D. ${45}^{\circ }$

Answer 1

The correct option is D ${45}^{\circ }$

We have range of projectile $\frac{u^2\sin 2\theta }{8}$

Therefore $\frac{u^2\sin 2\theta }{8}$

$\Rightarrow \frac{40400\times \sin 2\theta }{10}=40$

$\Rightarrow \sin 2\theta =\frac{40\times 10}{40400}$

$\Rightarrow \theta ={45}^0$

Hence, the answer is ${45}^0.$