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Question

The maximum velocity of a particle, executing simple harmonic motion with an amplitude $$7\ mm$$, is $$4.4\ m/s$$. The period of oscillation is 


A
100 s
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B
0.01 s
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C
10 s
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D
0.1 s
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Solution

The correct option is B $$0.01\ s$$
For a SHM, $$x=A\sin(\omega t +\phi)$$
Velocity, $$v=\dfrac{dx}{dt}=A\omega \cos(\omega t+\phi)$$
So, $$v_{max}=A\omega$$
or $$4.4=7\times 10^{-3}(2\pi/T)$$
or $$T=9.99\times 10^{-3}=10\times 10^{-3}=0.01 s$$

Physics

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