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Question

The maximum wavelength of light for photoelectric effect from a metal is $$200\ nm$$. The maximum kinetic energy of electron which is emitted by the radiation of wavelength $$100\ nm$$ will be:


A
12.4 eV
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B
6.2 eV
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C
100 eV
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D
200 eV
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Solution

The correct option is B $$6.2\ eV$$

Given that,

The maximum wave length $$\lambda_{0} =200\,nm$$

Radiation of wave length $$\lambda =100\,nm$$


We know that, the maximum K.E is

  $$ K.E=12400\left[ \dfrac{1}{\lambda }-\dfrac{1}{{{\lambda }_{0}}} \right] $$

 $$ K.E=12400\left[ \dfrac{1}{1000}-\dfrac{1}{2000} \right] $$

 $$ K.E=12400\times \dfrac{1}{2000} $$

 $$ K.E=6.2\,eV $$

Hence, the kinetic energy is $$6.2\ eV$$


Physics

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