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Question

The mean and the variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X=1) is

A
1/32
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B
1/16
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C
1/8
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D
1/4
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Solution

The correct option is A 1/32
Mean = np
=4
Variance =np(1p)
=2
Hence 4=2(1p)
p=12
Therefore n=4(2)
=8
Hence
P(1)=8C1128
=8256

=132

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