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Question

The mean kinetic energy of a gas molecule at 27$$^o$$C is 6.21 $$\times$$ 10$$^{-21}$$ Joule. Its value at 227$$^o$$ C will be


A
12.35×1021Joule
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B
11.35×1021Joule
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C
10.35×1021Joule
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D
9.35×1021Joule
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Solution

The correct option is C $$10.35 \times 10^{-21} Joule$$
Mean KE=$$\dfrac{3kT}{2}$$
so $$6.21\times 10^{-21}=3k\times 300/2$$
so $$k=1.38\times 10^{-23}$$
KE at 500 K ,$$KE=3\times 1.38\times 10^{-23}\times 500/2=10.35\times 10^{-21}\ Joule$$

Physics

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