Question

# The mean kinetic energy of a gas molecule at 27$$^o$$C is 6.21 $$\times$$ 10$$^{-21}$$ Joule. Its value at 227$$^o$$ C will be

A
12.35×1021Joule
B
11.35×1021Joule
C
10.35×1021Joule
D
9.35×1021Joule

Solution

## The correct option is C $$10.35 \times 10^{-21} Joule$$Mean KE=$$\dfrac{3kT}{2}$$so $$6.21\times 10^{-21}=3k\times 300/2$$so $$k=1.38\times 10^{-23}$$KE at 500 K ,$$KE=3\times 1.38\times 10^{-23}\times 500/2=10.35\times 10^{-21}\ Joule$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More