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Question

The mean of the following distribution is 52 and the frequency of class interval 30 - 40 is 'f'. Find 'f'.
Class IntervalFrequency10205203033040f405075060260706708013 [4 MARKS]

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Solution

Formula: 2 Marks
Solution: 2 Marks

ClassFrequencyxfxIntervale(f)1020515752030325753040f3535f40507453155060255110607066539070801375975f=25fx=1940+35f
Mean =fxf
52=1940+35f36+f
1872+52f=1940+35f
17f=19401872
17f=68f=4

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