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Question

The middle term in the expansion of (2x332x2)2n is


  1. (1)n2nCnxn

  2. 2nCnxn

  3. 2nCn

  4. None of these


Solution

The correct option is A

(1)n2nCnxn


(1)n2nCnxn

Here, n is even

Middle term in the given expansion =(2n2+1)th =(n+1)th term 

=2nCn(2x3)2nn(32x2)n

=(1)n2nCnxn

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