The midpoints of the sides of a triangle along with any of the vertices as the fourth point makes a parallelogram of area equal to
(a) 12(ar△ ABC)
(b) 13(ar△ ABC)
(c) 14(ar△ ABC)
(d) (ar△ ABC)
D, E and F are the midpoints of sides BC, AC and AB respectively.
On joining FE, we divide △ABC into 4 triangles of equal area.
Also, median of a triangle divides it into two triangles with equal area
Hence, the correct answer is option (a).