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Question

The minimum kinetic energy required for ionization of a hydrogen atom is $$E_1$$ in case electron is collided with hydrogen atom. It is $$E_2$$ if the hydrogen ion collided and $$E_3$$ when helium ion is collided. Then,


A
E1=E2=E3
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B
E1>E2>E3
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C
E1 < E2 < E3
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D
E1>E3>E2
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Solution

The correct option is D $$E_1 \mbox{ < } E_2 \mbox{ < } E_3$$
In case of hydrogen there is only $$1$$ proton. Hence $$Z = 1$$
For hydrogen ion, $$2$$ protons, $$Z = 2$$
For helium ion, $$Z = 3$$

Therefore, $$E = \dfrac{-13.6Z^2}{n^2}$$
Therefore, energy required is most in $$E_3 >E_2>E_1$$

Physics

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