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Reinforced Cement Concrete

Assumptions in Limit State of Flexure -II

The minimum s...

Question

The minimum strain at failure in tension steel having yield stress $f_{y} = 415$ MPa and Young's modulus $E_{s} = 200$ GPa, as per Limit State Method of Design, is

A

0.0025

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B

0.0038

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C

0.0045

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D

0.0050

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Solution

The correct option is B 0.0038
Minimum strain at failure in tension steel
$= 0.002 + \frac{0.87 f_{y}}{E_{s}} = 0.002 + \frac{0.87 \times 415}{2 \times 10^{5}} = 0.0038$

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