The minimum value of 9 tan-2 - - 4 cot-2 - is13-6-9-12-

The correct option is D 12 A.M. ≥ G.M. ⇒ 9 tan^2 θ + 4 cot^2 θ/2 ≥ √(4 cot^2 θ. 9 tan^2 θ) ⇒ 9 tan^2 θ + 4 cot^2 θ ≥ 12 Therefore, the minimum value is 12. ...

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Byju's Answer

Standard XI

Mathematics

Range of Trigonometric Expressions

The minimum v...

Question

The minimum value of $9 t a n^{2} θ + 4 c o t^{2} θ$ is

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Solution

The correct option is D
12

A.M. $\geq$ G.M.

$\Rightarrow$ $\frac{9 t a n^{2} θ + 4 c o t^{2} θ}{2}$ $\geq$ $\sqrt{4 c o t^{2} θ . 9 t a n^{2} θ}$

$\Rightarrow$ $9 t a n^{2} θ + 4 c o t^{2} θ$ $\geq$ 12

Therefore, the minimum value is 12.

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The minimum value of $9 t a n^{2} θ + 4 c o t^{2} θ$ is

The minimum value of
$9 {tan}^{2} θ + 4 {cot}^{2} θ$ is

Q. The minimum value of

9 {tan}^{2} θ + 4 {cot}^{2} θ

2 k

. Find the value of

k

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The minimum value of 9tan2θ+4cot2θ is

The correct option is D 12 A.M. ≥ G.M. ⇒ 9tan2θ+4cot2θ2 ≥ √4cot2θ.9tan2θ ⇒ 9tan2θ+4cot2θ ≥ 12 Therefore, the minimum value is 12.

The minimum value of $9 t a n^{2} θ + 4 c o t^{2} θ$ is

The correct option is D
12

A.M. $\geq$ G.M.

$\Rightarrow$ $\frac{9 t a n^{2} θ + 4 c o t^{2} θ}{2}$ $\geq$ $\sqrt{4 c o t^{2} θ . 9 t a n^{2} θ}$

$\Rightarrow$ $9 t a n^{2} θ + 4 c o t^{2} θ$ $\geq$ 12

Therefore, the minimum value is 12.