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Question

The minimum value of x satisfying the inequality 4x+0.572x4 is

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Solution

Given that4x+0.572x4 ....[1]Let 2x=tNow [1] can be written as 2t27t4 2t27t402t28t+t402t(t4)+1(t4)0(t4)(2t+1)0


12t40<t4 (As t=2x and 2x>0)0<2x42x<x[2, )
The minimum value of the given expression is -2.

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