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Question

The molar conductance of acetic acid at infinite dilution is $$\lambda _{\infty }$$. If the specific conductivity of 0.1M acetic acid is S, the apparent degree of ionisation is:



A
10000Sλ
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B
10Sλ
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C
λ100S
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D
100000λS
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Solution

The correct option is A $$\frac{10000S}{\lambda _{\infty }}$$
The degree of the dissociation is equal to the ratio of the molar conduction at dilution to the molar conduction at infinite dilution.  $$ \alpha =\cfrac { { 
\lambda  }_{ m } }{ { \lambda  }_{ \infty  
} }  $$.
The relationship between the molar conductivity and the specific conductance is $$  { \lambda  }_{ m }=\cfrac { \kappa 
\times 1000 }{ M }  $$ . 
Substitute $$\kappa =S $$ and $$ M=0.1  M $$  in the above equation.
$$ \alpha=\cfrac { { \cfrac { 1000\times S }{ 0.1 }  } }{ { \lambda  }_{ \infty  } }=\cfrac { { 10000S } }{ { \lambda  }_{ \infty  } } \quad \quad  $$

Option A is correct.

Chemistry

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