Question

# The molar conductance of acetic acid at infinite dilution is $$\lambda _{\infty }$$. If the specific conductivity of 0.1M acetic acid is S, the apparent degree of ionisation is:

A
10000Sλ
B
10Sλ
C
λ100S
D
100000λS

Solution

## The correct option is A $$\frac{10000S}{\lambda _{\infty }}$$The degree of the dissociation is equal to the ratio of the molar conduction at dilution to the molar conduction at infinite dilution.  $$\alpha =\cfrac { { \lambda }_{ m } }{ { \lambda }_{ \infty } }$$.The relationship between the molar conductivity and the specific conductance is $${ \lambda }_{ m }=\cfrac { \kappa \times 1000 }{ M }$$ . Substitute $$\kappa =S$$ and $$M=0.1 M$$  in the above equation.$$\alpha=\cfrac { { \cfrac { 1000\times S }{ 0.1 } } }{ { \lambda }_{ \infty } }=\cfrac { { 10000S } }{ { \lambda }_{ \infty } } \quad \quad$$Option A is correct.Chemistry

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