The molar conductivity of a 0.5mol/dm3 solution of AgNO3 with electrolytic conductivity of 5.76×10−3S cm−1 at 298 K is
The correct option is D 11.52 S cm2/mol
What this indicates is that if we have a cell of 1 mL electrolyte solution, its conductivity will be equal to k.
λm is conductivity of 1 mole of the electrolyte. That is why to obtain it we divide k by concentration to obtain the value for 1 mole and multiply it with 1000 (to extrapolate to 1 L from 1 mL).
=5.76×10−3×10+30.5=11.52 S cm2/mol