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Question

The molarity of the solution containing 2.8% (w/V) solution of KOH is:
(Given atomic mass of K=39 u)

A
0.1 M
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B
0.5 M
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C
0.2 M
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D
1 M
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Solution

The correct option is B 0.5 M
Weight of KOH=2.8 g
Volume of solution =100 mL
Molar mass of KOH= 39+16+1=56 g mol1
Molarity of the solution,
M=2.8×100056×100=2856=12=0.5 M

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