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Solubility Product

The molarity ...

Question

The molarity of urea (molar mass 60 g $m o l^{- 1})$ solution by dissolving 15 g of urea in 500 $c m^{3}$ of water is:

2 m o l d m^{- 3}

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0.5 m o l d m^{- 3}

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0.125 m o l d m^{- 3}

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0.0005 m o l d m^{- 3}

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Solution

The correct option is B $0.5 m o l d m^{- 3}$
Molarity is the number of moles of the solute present in one litre of the solution.
Molarity = $\frac{m o l e s}{v o l u m e (L)}$
Moles = $\frac{w e i g h t}{m o l e c u l a r w e i g h t}$
Molarity= $\frac{15}{60} \times \frac{1000}{500} = \frac{1}{2} = 0.5 m o l d m^{- 3}$

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