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B
0.75
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C
0.45
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D
0.55
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Solution
The correct option is A0.75
The balanced reactions are as follows:
C3H8+5O2→3CO2+4H2O(l) C3H4+3O2→2CO2+4H2O(l) Initially, PV=nRT 4.93×V=(a+b)RT .....(i) After combustion, pressure is due to the total moles of CO2. 11.8×V=(3a+2b)RT .....(ii) Divide equation (ii) by equation (i), we get 11.084.93=2.25=3a+2ba+b 2.25a+2.25b=3a+2b 0.25b=0.75a b=3a χC2H8 or χa=aa+b=aa+3a=14=0.25
χC2H4 or χb=1−0.25=0.75
Hence, the mole fraction of C2H4 in the mixture is 0.75.