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Question

# The mole fraction of component A in the vapour phase is χ1 and mole fraction of component A in liquid mixture is χ2 (PoA = vapour pressure of pure A; PoB = vapour pressure of pure B). Then the total vapour pressure of the liquid mixture is:

A
PoAχ2χ1
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B
PoAχ1χ2
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C
PoBχ1χ2
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D
PoBχ2χ1
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Solution

## The correct option is A PoAχ2χ1ANS: - Mole fraction of component A in vapor phase - x1In Liquid Phase x2Vapor Pressure of pure A=P∘AVaporer pressure of pure B=P∘BMole fraction of component A in the vapor phase is given byx1=PAPA+PBPA+PB=PAX1PB=PAX1−PA(1)According to Dalton's low PT=PA+PB(2) Where PA=P∘AX2(3) putting (1) and (3) in (2)PT=P0AX2+PAx1−PA=P0AX2+PPAX2X1−PσAx2PT=P0AX2x1

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