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Question

The mole fraction of water in a sulphuric acid solution is 0.85. Calculate the molality of the solution.

A
10 m
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B
9.8 m
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C
9.5 m
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D
9 m
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Solution

The correct option is B 9.8 m
mol fraction of water in solution = 0.85
So mol of acid = 1-0.85 = 0.15
Now

m=1000×molofacidnw×molecularwtofwater

m=1000×0.150.85×18

=9.8mol/kg
answer is B

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