The mole of gases $N H_{3}, C O_{2}$ and $H_{2}$ adsorbed by $1 g$ charcoal at $300 K$ and $1 a t m$ pressure shows the order:

C O_{2} > H_{2} > N H_{3}

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N H_{3} > C O_{2} > H_{2}

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H_{2} > C O_{2} > N H_{3}

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C O_{2} > N H_{3} > H_{2}

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Solution

The correct option is B $N H_{3} > C O_{2} > H_{2}$
The mole of gases
$N H_{3}, C O_{2}$ and $H_{2}$ adsorbed by 1 g charcoal at 300 K and 1 atm pressure shows the order of
$N H_{3} > C O_{2} > H_{2}$ .

This is based on higher value of van der waals' constant for attraction.
The strength of Van der Waals' forces is related to the size of atoms and molecules.The bigger the atom or molecule the bigger the Van der Waals' force.

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