Question

# The molecular shape and hybridization state of central atom in the molecule (A) are:

A
linear, sp
B
triangular, sp2
C
linear, sp3d
D
V-shape, sp3

Solution

## The correct option is C linear, $$sp^3d$$$$\underset {\text {(A)}} {XeF_2}+H_2 \rightarrow \underset {\text {(monoatomic colorles gas (C))}} {Xe}+\underset {\text {(highly associated liquid (B) used for etching glass)}} {2HF}$$$$\underset {\text {(A)}} {2XeF_2} +2H_2O \xrightarrow {hydrolysis} \underset {\text {(C)}} {2Xe}+\underset {\text {(B)}} {2H_2F_2}+\underset {\text {diatomic gas (A)}} {O_2}$$The ionization energy of $$O_2$$ is similar to the ionization energy of $$Xe$$$$HF+KF \rightarrow \underset {\text {(Addition compound (E))}} {KHF_2}$$$$\underset {\text {(E)}} {KHF_2} \xrightarrow [molten state] {electrolysis} \underset {\text {reactive gas(F)}} {F_2}$$$$\underset {\text {(F)}} {F_2}+\underset {\text {(C)}} {Xe} (1:1) \rightarrow \underset {\text {(A)}} {XeF_2}$$Thus the compound (A) is $$XeF_2$$ with linear shape and $$sp^3d$$ hybridization.Chemistry

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