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Ideal Gas Equation

The molecular...

Question

The molecular weights of oxygen and sulphur dioxide are $32$ and $64$ respectively. If 1 litre of oxygen at $15^{o} C$ and $740 m m$ pressure contains $N$ molecules, the number of molecules in $2$ litre of sulphur dioxide under the same conditions of temp. and pressure will be ?

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Solution

From ideal gas equation.
We have $P V = n R T$ ,
Moles for $O_{2} \Rightarrow P V R T \Rightarrow 1 \times 1 R T$
No. of molecules,
$N = N a R T$ ...(1)

For $S O_{2}$ ,
Moles of $S O_{2} \Rightarrow P V R T \Rightarrow 1 \times 2 R T$
No. of molecules,
$M = 2 N a R T$ ........(2)
Dividing both the equation. we get,
$N M = 12$
$M = 2 N$

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