Question

The molecularity and order with respect to $[OH{]}^{\ominus }$ is

• A. 0, 1
• B. 0, -1
• C. 1, 0
• D. -1, 0

Answer 1

Answer: (B)

0, -1

$l^{\ominus }+OC{l}^{\ominus }\to C{l}^{\ominus }+O{I}^{\ominus }$

1 1

$Rate=\frac{k\left[OC{l}^{\ominus }\right]\left[l^{\ominus }\right]}{[OH{]}^{\ominus }}$

So order with respect to $[OH{]}^{\ominus }$ is = -1

and molecularity is 0 as it is not present in balanced equation.