The molecule which has highest dipole moment amongest the following is:

{C H}_{4}

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{C H C l}_{3}

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{C C l}_{4}

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{C H l}_{3}

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Solution

The correct option is C ${C H C l}_{3}$
$C - C l$ bonds in $C H C l_{3}$ are more polar than $C - I$ bonds in $C H I_{3}$ . $C H_{4}$ and $C C l_{4}$ have zero dipole moments because of regular tetrahedron nature.

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Similar questions

C C l_{4}, C H C l_{3}

C H_{4}

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}, C C l_{4}

C C l_{4}

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C H_{4} = C C l_{4} < C H C l_{3} < C H_{2} C l_{2} < C H_{3} C l

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H_{2} O, C O_{2}, C C l_{4}, C H C l_{3}, N H_{3}, B F_{3}, B e F_{2}

C C l_{4}

C H C l_{3}

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