Question

The moment o inertia of a circular disc of radius $2m$ and mass $1kg$ about an axis passing through the center of mass but perpendicular to the plane of the disc is $2kg-m^2$. Its moment of inertia about an axis parallel to this axis but passing through the edge of the disc is (see the given figure.)

• A. $8kg-m^2$
• B. $4kg-m^2$
• C. $10kg-m^2$
• D. $6kg-m^2$

Answer 1

The correct option is D $6kg-m^2$

By applying difference of parallel axis present of inertia of vedy $I=Ig+M{R}^2$

$I=M.O.I$ about an axis passing through the center of the to plane of

$M=$use of vedy

$R=$ distance between axis and centre of mass

$I=(2+1\times 2^2)kg{m}^2$

$\Rightarrow 6kg{m}^2$