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Question

 The moment of inertia of a straight thin rod of mass $$M$$ , length $$L$$ about an axis perpendicular to its length and passing through its one end is : 


Solution

The moment of inertia by using parallel axis theorem, is given as,

$$I = \dfrac{{M{L^2}}}{{12}} + M{\left( {L/2} \right)^2}$$

$$I = \dfrac{{M{L^2}}}{3}$$

Thus, the moment of inertia of the rod about an axis perpendicular to its length and passing through its one end is $$\dfrac{{M{L^2}}}{3}$$.


Physics

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