You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Inertia

The moment of...

Question

The moment of Inertia of a uniform thin rod about its perpendicular bisector is $I$ . If the temperature of the rod is increased by $q$ the moment of Inertia about perpendicular bisector increases by (coefficient of linear expansion of material of the rod is $α$ )

Zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

α

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 I

α

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 I

α

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 2 I $α$ q
moment of inertia $α$ $(l e n g t h)^{2}$
so to calculate the change in moment of inertia, we will use $β$ = 2 x $α$
so change in moment of inertia = I x $β$ x q = 2I $α$ q

Suggest Corrections

Similar questions

Q. The moment of inertia of a rod about its perpendicular bisector is I. When the temperature of the rod is increased by

△ T

, the increase in the moment of inertia of the rod about the same axis is (Here ,

α

is the coefficient of linear expansion of the rod)

Q. If the temperature of a uniform rod is slightly increased by

Δ t

, its moment of inertia I about a perpendicular bisector increases by -

Q. When the temperature of a rod increases from

t

t + Δ t

, its moment of inertia about a perpendicular axis passing through its centre increases from

I

I + Δ I

. If

α

be the coefficient of linear expansion of the rod, then the value of

\frac{Δ I}{I}

Q. When the temperature of a rod increases from

T

T + Δ T

, the moment of inertia of the rod about an axis increases from

I

I + Δ I

. If the coefficient of linear expansion of rod is

α

, then find the ratio

\frac{Δ I}{I}

When the temperature of a rod increases from $t$ to $t + Δ t$ , the moment of inertia of the rod increases from $I$ to $I + Δ I$ . If the coefficient of linear expansion of the rod is $α$ , the ratio $\frac{Δ I}{I}$ is

Join BYJU'S Learning Program

The moment of Inertia of a uniform thin rod about its perpendicular bisector is I. If the temperature of the rod is increased by q the moment of Inertia about perpendicular bisector increases by (coefficient of linear expansion of material of the rod is α)

The correct option is C 2 Iαqmoment of inertia α (length)2so to calculate the change in moment of inertia, we will use β = 2 x αso change in moment of inertia = I x β x q = 2Iαq

The moment of Inertia of a uniform thin rod about its perpendicular bisector is $I$ . If the temperature of the rod is increased by $q$ the moment of Inertia about perpendicular bisector increases by (coefficient of linear expansion of material of the rod is $α$ )

The correct option is C 2 I $α$ q
moment of inertia $α$ $(l e n g t h)^{2}$
so to calculate the change in moment of inertia, we will use $β$ = 2 x $α$
so change in moment of inertia = I x $β$ x q = 2I $α$ q