Question

The momentum of a photon of a electromagnetic radiation is $3.3\times {10}^{-29}kgm{s}^{-1}$ .The frequency of the associated waves is $(h=6.6\times {10}^{-34}Js,c=3\times {10}^{8}m/s)$

• A. $3.0\times {10}^{3}Hz$
• B. $6.0\times {10}^{3}Hz$
• C. $7.5\times {10}^{12}Hz$
• D. $1.5\times {10}^{13}Hz$

Answer 1

The correct option is D $1.5\times {10}^{13}Hz$

$p=3.3\times {10}^{-29}kgm{s}^{-1}$

$\lambda =\frac{h}{mv}$

$\frac{c}{v}=\frac{h}{p}$

$v=\frac{pc}{h}$

$=\frac{3.3\times {10}^{-29}\times 3\times {10}^8}{6.6\times {10}^{-34}}$

$=1.5\times {10}^{13}Hz$

So, the answer is option (D).