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Question

The monkey B shown in figure is holding on to the tail of the monkey A which is climbing up a rope. The masses of the monkeys A and B are 5 kg and 2 kg respectively. If A can tolerate a tension of 30 N in its tail, what force maximum should it apply on the rope in order to carry the monkey B with it? Take g=10 m/s−2.
795973_c8d55e0d610d4ffcbaaf20e1831429df.png

A
105N
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B
108N
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C
10.5N
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D
100N
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Solution

The correct option is A 105N
Given, Mass,M1=5kg,m2=2kg,F=30N

So, TFg305a=0......1

302g2a=0.........2

Multiply by 2 in inequation 1 and equation by 5 and solving them then we get,

T=105N and a=5m/s2

Thus the maximum force applied by the monkey A to carry monkey B is 105N

991307_795973_ans_6244153369c7412197793e1e45cc1e9a.png

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