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Question

The mutual force of repulsion between two point charges kept a fixed distance apart is 9×105N when in vacuum and 4×105N when placed in a dielectric medium. What is the value of dielectric constant of the medium?

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Solution

Let the dielectric constant of the medium be K.
The force of interaction between the objects is FK when placed in
the medium of dielectric constant K and F is the force of interaction
between them in vacuum .
According to question ,
F=9×105N
and FK=4×105N
Dividing both these equations ,
we get dielectric constant , K = 2.25

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