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Question

The nth term of a sequence is given by an=2n+7. Show that it is an A.P. Also, find its 7th term.


Solution

an=2n+7

a1=2(1)+7=9

a2=2(2)+7=11

a3=2(3)+7=13

Hence the common difference (d),

a3a2=a2a1=2

The given sequence is A.P.

a7=2(7)+7=21

7th term is 21.

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