1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# The nearest star to our solar system is 4.29 light years away. How much is this distance in terms of parsecs? How much parallax would this star (named Alpha Centauri) show when viewed from two locations of the Earth six months apart in its orbit around the Sun ?

Open in App
Solution

## Given:The distance of the star is,=4.29 lyWe know that one light year is the distance travelled by light in one year.1 light year = 3×108×365×24×60×60 =94608×1011mTherefore, the distance in 4.29 ly can be written as:4.29 ly=405868.32×1011 mWe know that 1 Parsec is also the unit of distance and its value is:1 parsec=3.08×1016mNow, to express the distance in terms of parsec.4.29ly=405868.32×10113.08×1016=1.32 parsecThe diameter of the Earth's orbit is,d=3×1011mThe angle made by the star on the Earth's orbit can be given by: θ=3×1011405868.32×1011=7.39×10−6radBut, the angle covered in 1sec=4.85×10−6radSo, the parallax in viwing the star at two different positions of the Eart's orbit:for, 7.39×10−6rad=7.39×10−64.85×10−6=1.52"

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Order of Magnitude
PHYSICS
Watch in App
Join BYJU'S Learning Program