Question

# The nitrogen atoms in $$NH_3, NH_2^-$$ and $$NH_4^+$$ are all surrounded by eight electrons. When these species are arranged in increasing order of $$H-N-H$$ bond angle, correct order is

A
NH3,NH2,NH+4
B
NH+4,NH2,NH3
C
NH3,NH+4,NH2
D
NH2,NH3,NH+4

Solution

## The correct option is D $$NH_2^-, NH_3, NH_4^+$$Lone pair-lone pair repulsion is more than lone pair-bond pair or bond pair-bond pair repulsion.$$\\ { NH{ }^{ - } }_{ 2 }\\$$ has two lone pairs and two bond pairs but due to presence of lone pairs, angle $$H-N-H$$ is less than $$109^o$$.$$\\ { NH{ }^{ } }_{ 3 }\\$$ has three bond pairs and one lone pair. SInce one lone pair is less, angle is more than above case.$$\\ { NH{ }^{ + } }_{ 4 }\\$$ had four bond pairs. Angle is equal to $$109^o$$Hence, the correct increasing order of $$H-N-H$$ bond angle is $$NH_2^-, NH_3,NH_4^+$$.Chemistry

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