CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The nitrogen atoms in $$NH_3, NH_2^-$$ and $$NH_4^+$$ are all surrounded by eight electrons. When these species are arranged in increasing order of $$H-N-H$$ bond angle, correct order is


A
NH3,NH2,NH+4
loader
B
NH+4,NH2,NH3
loader
C
NH3,NH+4,NH2
loader
D
NH2,NH3,NH+4
loader

Solution

The correct option is D $$NH_2^-, NH_3, NH_4^+$$
Lone pair-lone pair repulsion is more than lone pair-bond pair or bond pair-bond pair repulsion.
$$\\ { NH{  }^{ - } }_{ 2 }\\ $$ has two lone pairs and two bond pairs but due to presence of lone pairs, angle $$H-N-H$$ is less than $$109^o$$.
$$\\ { NH{  }^{  } }_{ 3 }\\ $$ has three bond pairs and one lone pair. SInce one lone pair is less, angle is more than above case.
$$\\ { NH{  }^{ + } }_{ 4 }\\ $$ had four bond pairs. Angle is equal to $$109^o$$
Hence, the correct increasing order of $$H-N-H$$ bond angle is $$NH_2^-, NH_3,NH_4^+$$.

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image