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Question

The normality of $$10$$ volume $$H_2O_2$$ is nearly?


A
2.1
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B
3.4
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C
1.7
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D
5.1
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Solution

The correct option is C $$1.7$$
Normality of $$H_{2}O_{2}$$=Molarity$$\times$$valency factor of $$H_{2}O_{2}=\cfrac{\cfrac{x}{11.2}}{1(L)}\times 2$$
where $$x=$$ volume strength of $$H_{2}O_{2}$$
$$\therefore$$Normality=$$\cfrac{10}{11.2}\times 2 =1.7$$

Chemistry

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