Question

The normality of 10% ( weight / volume) acetic acid is:

• A. 1 N
• B. 10 N
• C. 1.67 N
• D. 0.83 N

Answer 1

Answer: (C)

1.67 N

$10\%\left(\frac{w}{v}\right)$ acetic acid means $10g$ acetic acid in $100ml$ water.

Thus, $100g$ of Acetic acid would be present in $1000ml$ of water.

$60g=1mole$ of acetic caid.

$\therefore 100g=\frac{100}{60}=1.67molesofC{H}_{3}C{O}_{2}H$

Thus, $1.67moles$ present in $1L$ of water.

i.e. the solution is $1.67M$

In case of $C{H}_{3}C{O}_{2}H,1Nsolution=1Msolution$

Thus, normality of $10\%$ acetic acid$=1.67$