Question

The normality of solution obtained by mixing $100mL$ of 0.2 M $H_2{SO}_4$ with $100mL$ of 0.2 M $NaOH$ is:

• A. 0.1
• B. 0.2
• C. 0.5
• D. 0.3

Answer 1

Answer: (A)

0.1

Normality= Molarity $\times$ Valency factor $..........\left(1\right)$

Valency factor for $H_{2}S{O}_4=2$ and that of $NaOH=1$

$\therefore N_1$ of $H_{2}S{O}_4=0.2\times 2=0.4$

$N_2$ of $NaOH=0.2\times 1=0.2$

We have, $N_1{V}_1+N_2{V}_2=N_R{V}_R⟶\left(2\right)$

$V_R=100+100=200$

$\therefore byequation\left(2\right),weget,$

$0.4\left(100\right)+0.2\left(100\right)=N_R\left(200\right)$

$\therefore 40-20=N_R\times 200$

$\therefore$ Normality of resultant solution $N_R=0.1$

Hence, the correct option is $A$