The normals at three points P,Q,R of the parabola y2=4ax meet in (h,k), the centroid of triangle PQR lies on
A
y=−a
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B
x=a
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C
y=0
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D
x=0
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Solution
The correct option is Cy=0 The centroid of the triangle formed by the cornomal points lies on the axis of the parabola.
So we can conclude that the centroid of ΔPQR must lie on y=0 or x-axis or the axis of parabola y2=4ax.