The nuclide 92 U 238 has all the following exceptA- 92 protonsB- 146 neutronsC- 92 electronsD- 238 nucleons

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Standard XII

Chemistry

Nucleus Common Terms

The nuclide 9...

Question

The nuclide 92U²³⁸ has all the following except

92 protons

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146 neutrons

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238 nucleons

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92 electrons

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Solution

The correct option is D
92 electrons

The nuclide (nucleus) consists of neutrons and protons (when combined called nucleons).

Thus,

No. of protons in 92U²³⁸ = 92,

No. of neutrons = 146 (238 – 92)

No. of nucleons = 238 (146 + 92)

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Q. An element E has two isotopes

(_{92}^{236} E a n d_{92}^{238} E)

and the average atomic mass of element E is 237, then the total number of nucleons in its most abundant isotope is

Q. Structures of nuclei of three atoms A, B and C are given below :
A has 90 protons and 146 neutrons
B has 92 protons and 146 neutrons
C has 90 protons and 148 neutrons
Based on the above data, which of these atoms are isotopes and which are isobars ?

Q. The atomic number (

A

) and mass number (

M

) of the nuclide formed when three alpha

α

and two

β

particles are emitted from

238_{92}^{238} U

Q. When

_{92} U^{238}

decays it emits an

α

- particle. The new nuclide in turn emits a

β

- particle to give another nuclide X. The mass number and atomic number of X are respectively :

Constituents of nuclei of three atoms A, B and C are given below:
A - 90 protons and 148 neutrons
B - 92 protons and 146 neutrons
C - 90 protons and 146 neutrons
Based on the above data, which of these atoms are isotopes?

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The nuclide 92U238 has all the following except

The correct option is D 92 electrons The nuclide (nucleus) consists of neutrons and protons (when combined called nucleons). Thus, No. of protons in 92U238 = 92, No. of neutrons = 146 (238 – 92) No. of nucleons = 238 (146 + 92)

The nuclide 92U²³⁸ has all the following except

The correct option is D
92 electrons

The nuclide (nucleus) consists of neutrons and protons (when combined called nucleons).

Thus,

No. of protons in 92U²³⁸ = 92,

No. of neutrons = 146 (238 – 92)

No. of nucleons = 238 (146 + 92)