The number N =999.....9 consists of exactly 2018 nines. Compute the number N^3. How many nines are there in N^3.
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Solution
Recall that any number consisting solely of k 9's has the form ( (10^k)−1 ) (since it is 1 smaller than the number 10^k), therefore 99999...with 2018 9's can be represented as N=(10^(2018))-1