Question

The number of all possible matrices of order $3\ast 3$ with each entry $0$ or $1$ is

• A. $9$
• B. $18$
• C. $27$
• D. $512$

Answer 1

The correct option is D $512$

The number of possible entries of $3\times 3$ matrix is $9$.

Every entry has two choices, $0$ or $1$

Thus, total number of choices is

$2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^9=512$

Hence, the correct option is D. $512$.