Question

The number of atoms present in $16g$ of oxygen is:

• A. $6.02\times {10}^{15}$
• B. $3.01\times {10}^{23}$
• C. $3.01\times {10}^{15}$
• D. $6.02\times {10}^{23}$

Answer 1

Answer: (D)

$6.02\times {10}^{23}$

1 mole of oxygen$=16g$

1 mole of oxygen contains$=6.022\times {10}^{23}atoms$

$\therefore$ $16$ of oxygen$=6.022\times {10}^{23}atoms$

Answer will be $\left(D\right)$