CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The number of common factors of  $$20, 36$$ and $$48$$ is 


Solution

Factors of $$ 20 = 1, 2, 4, 5, 10, $$ and $$ 20 $$
Factors of $$ 36 = 1, 2, 3, 4, 6, 9, 12, 18 $$ and $$ 36 $$
Factors of $$ 48 = 1, 2, 3, 4, 6, 8, 12, 16, 24 $$ and $$ 48 $$
Hence, common factors of $$20,36,48$$ are $$ 1, 2, 4.$$ So, total numbers of common factors is equal to $$3.$$

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image