Question

The number of common factors of  $$20, 36$$ and $$48$$ is

Solution

Factors of $$20 = 1, 2, 4, 5, 10,$$ and $$20$$Factors of $$36 = 1, 2, 3, 4, 6, 9, 12, 18$$ and $$36$$Factors of $$48 = 1, 2, 3, 4, 6, 8, 12, 16, 24$$ and $$48$$Hence, common factors of $$20,36,48$$ are $$1, 2, 4.$$ So, total numbers of common factors is equal to $$3.$$Mathematics

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