CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of common tangents to the circle x2+y2=4 and x2+y2−6x−8y−24=0 is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 1
Given circles are x2+y2=4 ...(1)
and x2+y26x8y24=0 ...(2)
Center of circle (1) is C1(0,0) and radius r1=2
Center of circle (2) is C2(3,4) and radius r2
Also d= distance between the centers =C1C2=5
Since d=r2r1, therefore the given circles touch internally, as such they can have just 1 common tangent at the point of contact

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Common Tangent to Two Circles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon